A nested for loop

Given three variables, i,j,k which take value 0 or 1, we want to find values for these values that cause a logical expression

```        ((1-i)*j + i*(1-k) + (1-j)*k)
```
to evaluate to 1, where * means 'and', 1- means 'not' and + means 'exclusive-or'. This can be solved using three nested for loops as shown in this slide.
```   import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.applet.*;

public class A extends Applet implements ActionListener {
JTextArea out;
JButton button;

public void init () {
setLayout(new FlowLayout());
add(new JScrollPane(out = new JTextArea(16,30)));
add(button = new JButton("Press Me"));
button.addActionListener(this);
}

public void doit() {
// Variables i,j,k will take value 0,1 only (Boolean)
// ((1-i)*j + i*(1-k) + (1-j)*k) is then a logic expression
// where '*' is 'and', '1-' is 'not' and '+' is 'exclusive-or'
// What values of i,j,k make true (that is, give it value 1)?
boolean done = false;
for (int i=0 ; i < 2 && !done ; i++) {
for (int j=0 ; j < 2 && !done ; j++) {
for (int k=0 ; k < 2 && !done ; k++) {
if ( (((1-i)*j + i*(1-k) + (1-j)*k) % 2) == 1 ) {
out.append("i="+i+" j="+j+" k="+k+"\n");
done = true;
}
}
}
}
if (!done) out.append("There is no solution!\n");
}

public void actionPerformed (ActionEvent evt) {  doit(); }
}
```